Trigonometry-JEE-Main-PYQ’s

Mathematics Questions

The value of \cot \left( \frac{\pi}{24} \right) is:
(A) \sqrt{2} + \sqrt{3} + 2 - \sqrt{6}
(B) \sqrt{2} + \sqrt{3} + 2 + \sqrt{6}
(C) \sqrt{2} - \sqrt{3} - 2 + \sqrt{6}
(D) 3\sqrt{2} - \sqrt{3} - \sqrt{6}
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If 15\sin^4\alpha + 10\cos^4\alpha = 6 , for some \alpha \in \mathbb{R} , then the value of 27\sec^6\alpha + 8\csc^6\alpha is equal to:
(A) 500
(B) 400
(C) 250
(D) 350
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If for x \in \left(0, \frac{\pi}{2}\right) , \log_{10} \sin x + \log_{10} \cos x = -1 and \log_{10} (\sin x + \cos x) = \frac{1}{2} (\log_{10} n - 1), \quad n > 0, then the value of n is equal to:
(A) 16
(B) 9
(C) 12
(D) 20
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If 0 < x, y < \pi and \cos x + \cos y - \cos(x + y) = \frac{3}{2}, then \sin x + \cos y is equal to:
(A) \frac{1 + \sqrt{3}}{2}
(B) \frac{1}{2}
(C) \frac{\sqrt{3}}{2}
(D) \frac{1 - \sqrt{3}}{2}
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If e^{(\cos^2 x + \cos^4 x + \cos^6 x + \ldots \infty)\log_e 2} satisfies the equation t^2 - 9t + 8 = 0, then the value of \frac{2\sin x}{\sin x + \sqrt{3} \cos x} \quad \left(0 < x < \frac{\pi}{2}\right) is:
(A) \sqrt{3}
(B) \frac{3}{2}
(C) 2\sqrt{3}
(D) \frac{1}{2}
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If L = \sin^2\left(\frac{\pi}{16}\right) - \sin^2\left(\frac{\pi}{8}\right) \quad \text{and} \quad M = \cos^2\left(\frac{\pi}{16}\right) - \sin^2\left(\frac{\pi}{8}\right), then:
(A) L = -\frac{1}{2\sqrt{2}} + \frac{1}{2} \cos \frac{\pi}{8}
(B) M = \frac{1}{2\sqrt{2}} + \frac{1}{2} \cos \frac{\pi}{8}
(C) M = -\frac{1}{4\sqrt{2}} + \frac{1}{4} \cos \frac{\pi}{8}
(D) L = \frac{1}{4\sqrt{2}} - \frac{1}{4} \cos \frac{\pi}{8}
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If the equation \cos^4 \theta + \sin^4 \theta + \lambda = 0 has real solutions for \theta , then \lambda lies in the interval:
(A) \left[ -\frac{3}{2}, -\frac{5}{4} \right]
(B) \left( -\frac{1}{2}, -\frac{1}{4} \right]
(C) \left( -\frac{5}{4}, -1 \right]
(D) [-1, -\frac{1}{2}]
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If x = \sum_{n=0}^{\infty} (-1)^n \tan^{2n} \theta \quad \text{and} \quad y = \sum_{n=0}^{\infty} \cos^{2n} \theta for 0 < \theta < \frac{\pi}{4} , then:
(A) x(1 + y) = 1
(B) y(1 - x) = 1
(C) y(1 + x) = 1
(D) x(1 - y) = 1
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The value of \cos^3\left(\frac{\pi}{8}\right)\cos\left(\frac{3\pi}{8}\right) + \sin^3\left(\frac{\pi}{8}\right)\sin\left(\frac{3\pi}{8}\right) is:
(A) \frac{1}{\sqrt{2}}
(B) \frac{1}{2}
(C) \frac{1}{4}
(D) \frac{1}{2\sqrt{2}}
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The equation y = \sin x \sin (x + 2) - \sin^2 (x + 1) represents a straight line lying in:
(A) first, second and fourth quadrants
(B) first, third and fourth quadrants
(C) second and third quadrants only
(D) third and fourth quadrants only
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