Trigonometry-JEE-Main-PYQ’s

Mathematics Questions

If the value of \frac{3 \cos 36^\circ + 5 \sin 18^\circ}{5 \cos 36^\circ - 3 \sin 18^\circ} is \frac{a\sqrt{5} - b}{c} , where a, b, c are natural numbers and \gcd(a, c) = 1 , then a + b + c is equal to:
(A) 54
(B) 52
(C) 50
(D) 40
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If \sin x = -\frac{3}{5} , where \pi < x < \frac{3\pi}{2} , then 80 \left( \tan^2 x - \cos x \right) is equal to
(A) 109
(B) 108
(C) 19
(D) 18
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Suppose \theta \in \left[0, \frac{\pi}{4}\right] is a solution of 4 \cos \theta - 3 \sin \theta = 1 . Then \cos \theta is equal to:
(A) \frac{6 - \sqrt{6}}{3\sqrt{6} - 2}
(B) \frac{4}{3\sqrt{6} + 2}
(C) \frac{6 + \sqrt{6}}{3\sqrt{6} + 2}
(D) \frac{4}{3\sqrt{6} - 2}
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If \tan A = \frac{1}{\sqrt{x(x^2 + x + 1)}}, \tan B = \frac{\sqrt{x}}{\sqrt{x^2 + x + 1}} and
\tan C = (x^{-3} + x^{-2} + x^{-1})^{1/2}, 0 < A, B, C < \frac{\pi}{2}, then A + B is equal to:
(A) C
(B) \pi - C
(C) 2\pi - C
(D) \frac{\pi}{2} - C
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The number of solutions, of the equation

e^{\sin x} - 2e^{-\sin x} = 2 , is:
(A) 0
(B) 1
(C) 2
(D) more than 2
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For \alpha, \beta \in (0, \pi/2), let 3 \sin(\alpha + \beta) = 2 \sin(\alpha - \beta) and a real number k be such that \tan \alpha = k \tan \beta. Then, the value of k is equal to:
(A) 5
(B) -2/3
(C) -5
(D) 2/3
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Solve the equation \cos \theta = \frac{1}{2} for \theta in the interval [0, 2\pi). The number of solutions is:
(A) 0
(B) 1
(C) 2
(D) 3
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The value of

36 \left(4 \cos^2 9^\circ - 1\right) \left(4 \cos^2 27^\circ - 1\right) \left(4 \cos^2 81^\circ - 1\right) \left(4 \cos^2 243^\circ - 1\right) is:
(A) 18
(B) 36
(C) 54
(D) 27
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If \tan 15^\circ + \frac{1}{\tan 75^\circ} + \frac{1}{\tan 105^\circ} + \tan 195^\circ = 2a, then the value of \left( a + \frac{1}{a} \right) is:
(A) 5 - \frac{3}{2}\sqrt{3}
(B) 4 - 2\sqrt{3}
(C) 2
(D) 4
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The set of all values of \lambda for which the equation
\cos^2 2x - 2\sin^4 x - 2\cos^2 x = \lambda
has a real solution x, is:
(A) [-2, -1]
(B) \left[-\frac{3}{2}, -1\right]
(C) [-2, -\frac{3}{2}]
(D) [-1, -\frac{1}{2}]
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