Circles-JEE-Main-PYQ’s

Mathematics Questions

Let the circle x^2 + y^2 = 4 intersect x-axis at the points A(a, 0), a > 0 and B(b, 0). Let P(2 \cos \alpha, 2 \sin \alpha), 0 < \alpha < \frac{\pi}{2} and Q(2 \cos \beta, 2 \sin \beta) be two points such that (\alpha - \beta) = \frac{\pi}{2}. Then the point of intersection of AQ and BP lies on :
(A) x^2 + y^2 - 4x - 4 = 0
(B) x^2 + y^2 - 4x - 4y = 0
(C) x^2 + y^2 - 4x - 4y - 4 = 0
(D) x^2 + y^2 - 4y - 4 = 0
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Let y = x be the equation of a chord of the circle C_1 (in the closed half-plane x \geq 0) of diameter 10 passing through the origin. Let C_2 be another circle described on the given chord as its diameter. If the equation of the chord of the circle C_2, which passes through the point (2, 3) and is farthest from the center of C_2, is x + ay + b = 0, then a - b is equal to
(A) -6
(B) 10
(C) 6
(D) -2
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Let a circle of radius 4 pass through the origin O, the points A(-\sqrt{3}a, 0) and B(0, -\sqrt{2}b), where a and b are real parameters and ab \neq 0. Then the locus of the centroid of \triangle OAB is a circle of radius
(A) \frac{7}{3}
(B) \frac{11}{3}
(C) \frac{5}{3}
(D) \frac{8}{3}
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Let the set of all values of r, for which the circles (x + 1)^2 + (y + 4)^2 = r^2 and x^2 + y^2 - 4x - 2y - 4 = 0 intersect at two distinct points be the interval (\alpha, \beta). Then \alpha\beta is equal to
(A) 21
(B) 24
(C) 20
(D) 25
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Let PQ and MN be two straight lines touching the circle x^2 + y^2 - 4x - 6y - 3 = 0 at the points A and B respectively. Let O be the centre of the circle and \angle AOB = \pi/3. Then the locus of the point of intersection of the lines PQ and MN is :
(A) x^2 + y^2 - 18x - 12y - 25 = 0
(B) x^2 + y^2 - 12x - 18y - 25 = 0
(C) 3(x^2 + y^2) - 12x - 18y - 25 = 0
(D) 3(x^2 + y^2) - 18x - 12y + 25 = 0
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A circle C of radius 2 lies in the second quadrant and touches both the coordinate axes. Let r be the radius of a circle that has centre at the point (2, 5) and intersects the circle C at exactly two points. If the set of all possible values of r is the interval (\alpha, \beta), then 3\beta - 2\alpha is equal to:
(A) 10
(B) 12
(C) 14
(D) 15
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Let circle C be the image of x^2 + y^2 - 2x + 4y - 4 = 0 in the line 2x - 3y + 5 = 0 and A be the point on C such that OA is parallel to x-axis and A lies on the right hand side of the centre O of C. If B(\alpha, \beta), with \beta < 4, lies on C such that the length of the arc AB is (1/6)^{\text{th}} of the perimeter of C, then \beta - \sqrt{3}\alpha is equal to:
(A) 4 - \sqrt{3}
(B) 3
(C) 4
(D) 3 + \sqrt{3}
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Let the equation of the circle, which touches x-axis at the point (a, 0), a > 0 and cuts off an intercept of length b on y-axis be x^2 + y^2 - \alpha x + \beta y + \gamma = 0. If the circle lies below x-axis, then the ordered pair (2a, b^2) is equal to:
(A) (\alpha, \beta^2 + 4\gamma)
(B) (\alpha, \beta^2 - 4\gamma)
(C) (\gamma, \beta^2 - 4\alpha)
(D) (\gamma, \beta^2 + 4\alpha)
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Let the line x + y - 1 = 0 meet the circle x^2 + y^2 = 4 at the points A and B. If the line perpendicular to AB and passing through the mid-point of the chord AB intersects the circle at C and D, then the area of the quadrilateral ABCD is equal to:
(A) \sqrt{14}
(B) 3\sqrt{7}
(C) 2\sqrt{14}
(D) 5\sqrt{7}
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Let a circle C pass through the points (4, 2) and (0, 2), and its centre lie on 3x + 2y + 2 = 0. Then the length of the chord of the circle C, whose mid-point is (1, 2), is:
(A) 4\sqrt{2}
(B) 2\sqrt{2}
(C) 2\sqrt{3}
(D) \sqrt{3}
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